Math, asked by Anonymous, 10 months ago

Solve the following equations by trial and error method:

(i) 5p + 2 = 17
(ii) 3m – 14 = 4

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Answers

Answered by Anonymous
6

(i) 5p + 2 = 17

  • If p = 0 then 5(0) + 2 = 17, 0 + 2 ≠ 17
  • If p = 1 then 5(1) + 2 = 17, 5 + 2 ≠ 17
  • If p = 2 then 5(2) + 2 = 17, 10 + 2 ≠ 17
  • If p = 3 then 5(3) + 2 = 17, 15 + 2 =17

p = 3 is the solution to the given equation 5p + 2 = 17.

(ii) 3m – 14 = 4

  • If m = 0 then 3(0) – 14= 0 – 14 = – 14 ≠ 4
  • If m = 1 then 3(1) – 14= 3 – 14 ≠ -11
  • If m = 2 then 3(2) – 14 =6 – 14 ≠ – 8
  • If m = 3 then 3(3) – 14 ≠ -5
  • If m = 4 then 3(4) – 14 ≠-2
  • If m = 5 then 3(5) – 14 ≠1
  • If m = 6 then 3(6) – 14 = 4

LHS = RHS

m = 6 is the solution to the given equation 3m – 14 = 4

Answered by Anonymous
1

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