Math, asked by ishika603, 1 month ago

Solve the following equations. Check your result in each case. 2x-1/3-6x-2/5-1/3​

Answers

Answered by christiananrich23
0

Answer:

Answer:

The value of x is x=-\frac{1}{2}x=−

2

1

Step-by-step explanation:

Given : Expression \frac{2x-1}{3}-\frac{6x-2}{5}=\frac{1}{3}

3

2x−1

5

6x−2

=

3

1

To find : Solve the expression ?

Solution :

Expression \frac{2x-1}{3}-\frac{6x-2}{5}=\frac{1}{3}

3

2x−1

5

6x−2

=

3

1

Taking LCM,

\frac{5(2x-1)-3(6x-2)}{15}=\frac{1}{3}

15

5(2x−1)−3(6x−2)

=

3

1

\frac{10x-5-18x+6}{15}=\frac{1}{3}

15

10x−5−18x+6

=

3

1

\frac{1-8x}{15}=\frac{1}{3}

15

1−8x

=

3

1

Cross multiply,

3(1-8x)=153(1−8x)=15

3-24x=153−24x=15

24x=-1224x=−12

x=-\frac{12}{24}x=−

24

12

x=-\frac{1}{2}x=−

2

1

Therefore, The value of x is x=-\frac{1}{2}x=−

2

1

Answered by aditya469829
0

Answer:

Answer:

The value of x is x=-\frac{1}{2}x=−21

Step-by-step explanation:

Given : Expression \frac{2x-1}{3}-\frac{6x-2}{5}=\frac{1}{3}32x−1−56x−2=31

To find : Solve the expression ?

Solution :

Expression \frac{2x-1}{3}-\frac{6x-2}{5}=\frac{1}{3}32x−1−56x−2=31

Taking LCM,

\frac{5(2x-1)-3(6x-2)}{15}=\frac{1}{3}155(2x−1)−3(6x−2)=31

\frac{10x-5-18x+6}{15}=\frac{1}{3}1510x−5−18x+6=31

\frac{1-8x}{15}=\frac{1}{3}151−8x=31

Cross multiply,

3(1-8x)=153(1−8x)=15

3-24x=153−24x=15

24x=-1224x=−12

x=-\frac{12}{24}x=−2412

x=-\frac{1}{2}x=−21

Therefore, The value of x is x=-\frac{1}{2}x=−21

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