Solve the following equations for x and y:
log₁₀(xy) = 2, log₁₀(x/y) + 2 log₁₀ 2 = 2
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Answer:
this is not social it's is math
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x= 50, y = 2
Explanation:
Given log₁₀(xy) = 2
log x + log y = 2
log x = 2- log y-----(1)
Given log₁₀(x/y) + 2 log₁₀ 2 = 2
log x - log y + 2 log 2 = 2 -------(2)
Substituting (1) in (2), we get:
2- log y - log y + 2 log 2 = 2
-2 log y = -2 log 2
-2 will get cancelled on both sides.
log y = log 2.
So y = 2.
Given log₁₀(xy) = 2
Substituting y = 2, we get log2x = 2.
Common logarithm of 100 is 2, so we write the right-hand side as log 100.
log2x = log100
So 2x = 100, hence x = 50
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