Question

solve the following equations...

full solution pls​

Answer 1

$\bf\huge\underline{\underline{ To \: Find:- }}$

• $\sf\frac{4x - 3}{3} - \frac{2x + 1}{7} = 2$

• $\sf\frac{x + 9}{2} - \frac{5x - 6}{3} = \frac{4x - 3}{3}$

$\bf\huge\underline{\underline{ Answer :- }}$

$\boxed{ \sf\frac{4x - 3}{3} - \frac{2x + 1}{7} = 2}$

$\rightarrow \sf \frac{7(4x - 3) - (2(2x + 1)}{7 \times 3} = 2$

$\rightarrow \sf \frac{28x - 21 - (6x + 3)}{21} = 2$

$\rightarrow \sf \frac{28x - 6x - 21 - 3}{21} = 2$

$\rightarrow \sf 22x - 24 = 42$

$\rightarrow \sf 22x = 66$

$\blue{\rightarrow \sf x = \frac{66}{22}}$

$\blue{\rightarrow \sf \: \: \underline{ \underline{ x = 3}}}$

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• $\boxed{\sf\frac{x + 9}{2} - \frac{5x - 6}{3} = \frac{4x - 3}{3}}$

$\rightarrow \sf \frac{3(x + 9) - (2(5x - 6)}{2 \times 3} = \frac{4x - 3}{3}$

$\rightarrow \sf \frac{3x + 27 - (10x - 12)}{6} = \frac{4x - 3}{3}$

$\rightarrow \sf \frac{3x - 10x + 27 + 12}{6} = \frac{4x - 3}{3}$

$\rightarrow \sf \frac{ - 7x + 39}{6} = \frac{4x - 3}{3}$

$\rightarrow \sf \: - 7x + 39 = \frac{6(4x - 3)}{3}$

$\rightarrow \sf - 7x + 39 = 2(4x - 3)$

$\rightarrow \sf - 7x + 39 =8x - 6$

$\rightarrow \sf 8x + 7x = 39 + 6$

$\rightarrow \sf 15x = 45$

$\blue{\rightarrow \sf x = \frac{45}{15}}$

$\blue{\rightarrow \sf \underline{ \underline{ x = 3}}}$

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Answer 2

Answer:

I ) x= 3

II) x= 3

Step-by-step explanation:

$\frac{4x - 3}{3} - \frac{2x + 1}{7} = 2 \\ \\ \frac{7(4x - 3) - 3(2x + 1)}{3(7)} = 2 \\ \\ \frac{28x - 21 - 6x - 3}{21} = 2 \\ \\ 22x - 24 = 42 \\ \\ 22x = 66 \\ \\ x = 3$

$\\ \\ \\ \\ \frac{x + 9}{2} - \frac{5x - 6}{3} = \frac{4x - 3}{3} \\ \\ by \: cross \: multiplication of \: lhs \: \\ \\ \frac{3x + 27 - 10x + 12}{6} = \frac{4x -3}{3} \\ \\ \frac{ - 7x + 39}{2} = \frac{4x - 3}{1} \\ \\ - 7x + 39 = 8x - 6 \\ \\ 8x + 7x= 39 + 6 \\ \\ 15x = 45 \\ \\ x = 3$