Question

Solve the following equations:-
(i) x(2x + 5) = 0
(ii) 6z^2 - 6 + 5z = 0

Can anyone help me with these equations from "quadratic equations in one variable" of class 10?

Answer 1

x=0 or x= -5/2

z=2/3 or z = -3/3

i)

• x(2x+5) =0

• it can only be zero if x=0 or

2x+5=0

• 2x+5=0

• 2x=-5

• x= -5/2

• so x(2x+5) =0 has two solution i.e.

x=0 or x= -5/2

ii)

• 6z²+5z-6=0

• 6z² +9z-4z-6 =0

• 3z(2z+3)-2(2z+3)=0

• (3z-2)(2z+3)=0

• it can only be zero when

3z-2 = 0 or 2z+3 =0

z=2/3 or z = -3/3