Question

Solve the following equations ) ((m-1))/2 - (( m-2))/3 = (( m-4 ))/7

Answer 1

Answer:

m - (m - 1)/2 = 1- (m - 2)/3

(2m - m + 1)/2 = (3 - m + 2)/3

(m + 1)/2 = ( 5 - m)/3

3(m + 1) = 2(5 - m)

3m + 3 = 10 - 2m

3m + 2m = 10 - 3

5m = 7

m = 7/5

Step-by-step explanation:

plz mark as brainliest..

Answer 2

Answer:

$\huge\boxed{m=-31}$

Step-by-step explanation:

$\dfrac{m-1}{2}-\dfrac{m-2}{3}=\dfrac{m-4}{7}\\\\LCM(2,\ 3,\ 7)=42\\\\42\!\!\!\!\!\diagup^{21}\cdot\dfrac{m-1}{2\!\!\!\!\diagup_1}-42\!\!\!\!\!\diagup^{14}\cdot\dfrac{m-2}{3\!\!\!\!\diagup_1}=42\!\!\!\!\!\diagup^6\cdot\dfrac{m-4}{7\!\!\!\!\diagup_1}\\\\21(m-1)-14(m-2)=6(m-4)\\\\\text{use the distributive property}\ a(b+c)=ab+ac\\\\(21)(m)+(21)(-1)+(-14)(m)+(-14)(-2)=(6)(m)+(6)(-4)\\\\21m-21-14m+28=6m-24\\\\\text{combine like terms}\\\\(21m-14m)+(-21+28)=6m-24$

$7m+7=6m-24\qquad|\text{subtract}\ 6m\ \text{from both sides}\\\\m+7=-24\qquad\text{subtract 7 from both sides}\\\\m=-31$