Question

Solve the following equations:


Q.1 (3x – 2) /5 + (x + 3) /2 – 3/10
= x/2


Q.2 (x- 7) /3 = ( x+ 5) /4


Q.3 4(y- 1) – 3(y + 7) +5(y +8) =0​

Answer 1

Answer:

Q1 = 2(3x-2)/10+5(x+3)/10 -3 /10 =x/2

by solving

12x= 8

x=8/12

x=2/3

Q2 =x-7 /3 =x+5/4

4(x-7)=3(x+5)

by solving

x =43

I hope this will help you