Question

Solve the following equations - show formula used AND each step required to find solution.A fruit hangs from a tree and is about to fall to the ground of 10 meters height. It has a potential energy of 22.5 J. What is the mass of the fruit?

Answer 1

Answer:-

$\red{\bigstar}$ The mass of the fruit is

$\large\leadsto\boxed{\sf\purple{0.225 \: kg}}$

• Given:-

Distance from the ground [h] = 10 m

Potential energy [P.E] = 22.5 J

• To Find:-

Mass of the fruit [m] = ?

• Solution:-

We know,

$\orange{\bigstar}$$\large\boxed{\sf\green{Potential \: energy[P.E] = mgh}}$

here,

P.E = 22.5 J

g = 10 m/s²

h = 10 m

m = ?

Using the formula:-

→ 22.5 = m × 10 × 10

→ 22.5 = m × 100

→ m = $\sf{\dfrac{22.5}{100}}$

→ m = 0.225 kg

Therefore, the mass of the fruit is 0.225 kg.

$\red{\bigstar}$ Know more:-

• Energy is defined as the capacity to do work.

• There are various types of energies, such as wind energy, electrical energy, kinetic energy, potential energy, etc.

• S.I unit of Energy is Joule (J). Other units are calories [C] and ergs.

Answer 2

Answer:-

$\red{\bigstar}$ The mass of the fruit is

$\large\leadsto\boxed{\sf\purple{0.225 \: kg}}$

• Given:-

Distance from the ground [h] = 10 m

Potential energy [P.E] = 22.5 J

• To Find:-

Mass of the fruit [m] = ?

• Solution:-

We know,

$\orange{\bigstar}$$\large\boxed{\sf\green{Potential \: energy[P.E] = mgh}}$

here,

P.E = 22.5 J

g = 10 m/s²

h = 10 m

m = ?

Using the formula:-

→ 22.5 = m × 10 × 10

→ 22.5 = m × 100

→ m = $\sf{\dfrac{22.5}{100}}$

→ m = 0.225 kg

Therefore, the mass of the fruit is 0.225 kg.

$\red{\bigstar}$ Know more:-

• Energy is defined as the capacity to do work.

• There are various types of energies, such as wind energy, electrical energy, kinetic energy, potential energy, etc.

• S.I unit of Energy is Joule (J). Other units are calories [C] and ergs.