Question

Solve the following equations using systematic method.​

Answer 1

(e)

• $\sf 4x - \frac{7}{2} = \frac{1}{2}$

• $\sf 4x = \frac{1}{2} + \frac{7}{2}$

• $\sf 4x = \frac{8}{2}$

• $\sf 4x = \frac{\cancel{8}^{\: \: 4 × \cancel{2}} }{\cancel{2}}$

• $\sf 4x = 4$

• $\sf x = \frac{4}{4}$

• $\purple{\underline{\boxed{\bf x = 1}}}$

(f)

• $\sf 6z + 6 = - 12$

• $\sf 6z = - 12 - 6$

• $\sf 6z = - 18$

• $\sf z = \frac{\cancel{-18}^{\: \: \cancel{6} × -3 } }{\cancel{6}}$

• $\purple{\underline{\boxed{\bf z = -3 }}}$

(i)

• $\sf 3y + 4 = - 5$

• $\sf 3y = - 5 - 4$

• $\sf 3y = - 9$

• $\sf y = \frac{\cancel{-9}^{\: \: -3 × \cancel{3} }}{\cancel{3}}$

• $\purple{\underline{\boxed{\bf y = -3 }}}$

(j)

• $\sf \frac{2r}{5} - 1 = 3$

• $\sf \frac{2r}{5} = 3 + 1$

• $\sf \frac{2r}{5} = 4$

• $\sf 2r = 4 × 5$

• $\sf r = \frac{\cancel{4}^{\: \: 2 × \cancel{2}} × 5 }{\cancel{2}}$

• $\sf r = 2 × 5$

• $\sf \purple{\underline{\boxed{\bf r = 10 }}}$

I hope it helps you ❤️✔️