Question

Solve the following equations using the general formula :
${x}^{2} - 3\sqrt{6} + 12 = 0$
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Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

${x}^{2} - 3\sqrt{6} x+ 12 = 0$

${x}^{2} - 2 \sqrt{6} x - \sqrt{6} x + 12 = 0 \\ \\ x(x - 2 \sqrt{6} ) - \sqrt{6} (x - 2 \sqrt{6} ) = 0 \\ \\ (x - \sqrt{6} )(x - 2 \sqrt{6} ) = 0 \\ \\ x = \sqrt{6} \\ \\ x = 2 \sqrt{6}$

We can use formula as well....but this is convenient method........