Question

Solve the following equations using the general formula:
${x}^{2} - 3 \sqrt{6x} + 12 = 0$
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Answer 1

Answer:

x = 2 root 6

x = root 6

x = 2 root 6

x = root 6

Answer 2

Answer:

√6 and 2√6

Step-by-step explanation:

x^2-3√6x+12=0

x^2-2√6x-√6x+12=0

x(x-2√6)-√6(x-2√6)=0

(x-2√6)(x-√6)=0

x-2√6)=0 or

(x-√6)=0

x= 2√6

and x= √6