Math, asked by kumarsinghvinay4323, 7 months ago

Solve the following equations using the trial and error method 11+2x=19​

Answers

Answered by saritabhatt780
3

Answer:

For trial and error method

First,x = 1

11 + 2x = 19

11 + 2 × 1 = 19

11 + 2 = 19

13 = 19

.°. L.H.S not equals to R.H.S

Second,x = 2

11 + 2x = 19

11 + 2 × 2 = 19

11 + 4 = 19

15 = 19

.°. L.H.S not equals to R.H.S

Third,x = 3

11 + 2x = 19

11 + 2 × 3 = 19

11 + 6 = 19

17 = 19

.°. L.H.S not equals to R.H.S

Fourth,x = 4

11 + 2x = 19

11 + 2 × 4 = 19

11 + 8 = 19

19 = 19

.°. L.H.S = R.H.S

Please mark me as the brainliest answer

Answered by Unknown0708
3

Answer:

Let x be 1

then 11+2 is not equal to 19

Let x be 2

then 11+4 is not equal to 19

Now let x be 3

then 11+6 is not equal to 19

Now let x be 4

then 11+8 is equal to 19

Therefore value of x is 4

Please mark as brainliest.

Similar questions