Question

Solve the following Equations using transposing method: 1. 2r - 5 = 27/4 2. 4(2-z) = 24 3. 23 - (z-8) = 9 4. 8 = 5(z-2) 5. 3(z - 3/5) = 14 please explain with steps if possible Thank you

Answer 1

Answer:

(1)

$2r - 5 = \frac{27}{4}$

$4(2r - 5) = 27$

$8r - 20 = 27$

$8r = 47$

$r = \frac{47}{8}$

$r = 5.875$

(2)

$4(2 - z) = 24$

$2 - z = \frac{24}{4}$

$2 - z = 6$

$- z = 6 - 2$

$- z = 4$

$z = - 4$

(3)

$23 - (z - 8) = 9$

$23 - z + 8 = 9$

$31 - z = 9$

$- z = 9 - 31$

$z = 31 - 9$

$z = 22$

(4)

$8 = 5(z - 2)$

$8 = 5z - 10$

$18 = 5z$

$\frac{18}{5} = z$

$3.6 = z$

Hope this helps.

Thanks.