solve the following equationsby using cramers rule 1x-2y+3z=0,2x+1y-3z=5,-1x-1y+2z=3
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Solve the following equations using Cramer's Rule
2x−y+3z=9,x+y+z=6,x−y+z=2
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Δ=
∣
∣
∣
∣
∣
∣
∣
∣
2
1
1
−1
1
−1
3
1
1
∣
∣
∣
∣
∣
∣
∣
∣
=2(1+1)−(−1)(1−1)+3(−2)=4−6=−2
Now, Δ
x
=
∣
∣
∣
∣
∣
∣
∣
∣
9
6
2
−1
1
−1
3
1
1
∣
∣
∣
∣
∣
∣
∣
∣
=14
Δ
y
=
∣
∣
∣
∣
∣
∣
∣
∣
2
1
1
9
6
2
3
1
1
∣
∣
∣
∣
∣
∣
∣
∣
=−2
Δ
z
=
∣
∣
∣
∣
∣
∣
∣
∣
2
1
1
−1
1
−1
9
6
2
∣
∣
∣
∣
∣
∣
∣
∣
=−6
So,According to Cramer's Rule x=
Δ
Δ
x
=
−2
14
=−7
y=
Δ
Δ
y
=
−2
−2
=1
z=
Δ
Δ
z
=
−2
−6
=3
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