solve the following example -:
two tungstungs bulb of wattege 100 W and 60 W power work on 220 volts potential difference. if they are connected in parallel how much current flow in the main conductor?
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Potential remains same in the resistors when they are connected in the parallel.∴ Potential in both the bulbs will be same.
Now,
For First Tungsten Bulb,
Power=100W.
Potential=220V.
Power=Potential∗Current.
Current=220100
Current=0.45A.
For second Tungsten bulbs,
Power =60W.
Potential =220V.
Current =22060=0.27A.
Now, Total current flowing = Current in 1st bulb + Current in 2nd bulb.=0.45+0.27=0.72A.
Hence, the total current flowing in the main conductor is 0.72A.
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