Solve the following exponential equations and find the value of x: 1) 3^× + 3^× = 243
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3x=2433x=243
Take the log base 3 of both sides to cancel out it’s corresponding base, 3.
log3(3x)=log3(243)log3(3x)=log3(243)
x=log3(243)x=log3(243)
log3(243)=5log3(243)=5, because 35=24335=243.
x=5 x=5 ← final answer.
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