solve the following Exponentuial equation
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(√3)^x = (3)^8
then √3^x = (√3^2)^8
then √3^x = √3^16 (as ((a)^b)^c = a^bc)
So x = 16
then √3^x = (√3^2)^8
then √3^x = √3^16 (as ((a)^b)^c = a^bc)
So x = 16
Answered by
1
Your answer is in the pic.
Hope it helps u buddy :-)
Hope it helps u buddy :-)
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udit43:
Most welcome dear.
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