Question

Solve the following following equation for x: 9 x^-9(a+b)x+(2a^+5ab+2b^)=0

Answer 1

Answer:

9x²-9(a+b)x+(2a²+5ab+2b²)

first we will take 

(2a²+5ab+2b²)and factorize it

⇒2a²+4ab+ab+2b²

⇒2a(a+2b)+b(a+2b)

⇒(2a+b)(a+2b)

now,9x²-9(a+b)x+(2a+b)(a+2b)=0

9x²-3(2a+b)x-3(a+2b)x+(2a+b)(a+2b)=0

3x(3x-(2a+b))-(a+2b)(x-(2a+b))=0

(3x-(a+2b))(3x-(a+2b))=0

∴x=(a+2b)/3  and x=(2a+b)/3

Answer 2

Please mark as brainliest answer

9x²-9(a+b)x+(2a²+5ab+2b²)

first we will take 

(2a²+5ab+2b²)and factorize it

⇒2a²+4ab+ab+2b²

⇒2a(a+2b)+b(a+2b)

⇒(2a+b)(a+2b)

now,9x²-9(a+b)x+(2a+b)(a+2b)=0

9x²-3(2a+b)x-3(a+2b)x+(2a+b)(a+2b)=0

3x(3x-(2a+b))-(a+2b)(x-(2a+b))=0

(3x-(a+2b))(3x-(a+2b))=0

∴x=(a+2b)/3  and x=(2a+b)/3