solve the following for the values of x and y
(x+iy)(3+i)=2+4i
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Step-by-step explanation:
LHS=3x++ix+3iy+i^2y
=3x+ix+3iy-y
On comparing with RHS
2=3x-y. eq.1
4i=i (X+3y)
4=X+3y. e.q.2
×eq1 by 2 and solving eq1&2 by elimination,we get.
4=6x-3y
4=X +3y
- - -
0=5x-0
X=0
y=-2
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