Question

Solve the following for value of x :-

$\sf{ \dfrac{2x}{5} + 4 = 10 }$


$\sf{ 2x - 3 = 7 }$​

Answer 1

Answer:

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Answer 2

Given :

• $\sf{ \dfrac{2x}{5} + 4 = 10 }$

To Find :

• Value of x = ?

SolutioN :

$\dag$ Let's Calculate the Value of x :

${\longmapsto{\qquad{\sf{ \dfrac{2x}{5} + 4 = 10 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ \dfrac{2x}{5} = 10 - 4 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ \dfrac{2x}{5} = 6 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ 2x = 6 \times 5 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ 2x = 30 }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ x = \dfrac{30}{2} }}}} \\ \\ \\ \ {\longmapsto{\qquad{\sf{ x = \cancel\dfrac{30}{2} }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\purple{\pmb{\frak{ x = 15 }}}}}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

$\dag$ Therefore :

❛❛ Value of x is 15 . ❜❜

$\\ {\underline{\rule{200pt}{3pt}}}$

Given :

• 2x - 3 = 7

To Find :

• Value of x = ?

SolutioN :

$\dag$ Let's Calculate the Value of x :

${\dashrightarrow{\qquad{\sf{ 2x - 3 = 7 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ 2x = 7 + 3 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ 2x = 10 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ x = \dfrac{10}{2} }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ x = \cancel\dfrac{10}{2} }}}} \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\pink{\pmb{\frak{ x = 5 }}}}}}}}$

$\\ \qquad{\rule{150pt}{1pt}}$

$\dag$ Therefore :

❛❛ Value of x is 5 . ❜❜

$\\ {\underline{\rule{200pt}{3pt}}}$