Solve the following for x. 1/2a+b+2x=1/2a+1/b+1/2x ?????? anyone plzz help urgent for model who ever answers will be BRAINLIEST if it is right
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Given Equation is:
![\frac{1}{2a+b+2x} = \frac{1}{2a} + \frac{1}{b} + \frac{1}{2x} \frac{1}{2a+b+2x} = \frac{1}{2a} + \frac{1}{b} + \frac{1}{2x}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B2a%2Bb%2B2x%7D+%3D+%5Cfrac%7B1%7D%7B2a%7D+%2B+%5Cfrac%7B1%7D%7Bb%7D+%2B+%5Cfrac%7B1%7D%7B2x%7D+)
![\frac{1}{2a+b+2x} - \frac{1}{2x} = \frac{1}{2a} + \frac{1}{2b} \frac{1}{2a+b+2x} - \frac{1}{2x} = \frac{1}{2a} + \frac{1}{2b}](https://tex.z-dn.net/?f=+%5Cfrac%7B1%7D%7B2a%2Bb%2B2x%7D+-+%5Cfrac%7B1%7D%7B2x%7D+%3D+%5Cfrac%7B1%7D%7B2a%7D+%2B+%5Cfrac%7B1%7D%7B2b%7D+)
On cross-multiplication, we get
![\frac{2x - 2a - b - 2x}{2x(2a + b + 2x)} = \frac{2a + b}{2ab} \frac{2x - 2a - b - 2x}{2x(2a + b + 2x)} = \frac{2a + b}{2ab}](https://tex.z-dn.net/?f=+%5Cfrac%7B2x+-+2a+-+b+-+2x%7D%7B2x%282a+%2B+b+%2B+2x%29%7D++%3D++%5Cfrac%7B2a+%2B+b%7D%7B2ab%7D+)
![\frac{-(2a+b)}{2x(2a+b+2x)} = \frac{2a+b}{2ab} \frac{-(2a+b)}{2x(2a+b+2x)} = \frac{2a+b}{2ab}](https://tex.z-dn.net/?f=+%5Cfrac%7B-%282a%2Bb%29%7D%7B2x%282a%2Bb%2B2x%29%7D+%3D++%5Cfrac%7B2a%2Bb%7D%7B2ab%7D+)
![\frac{-1}{2x(2a+b+2x)} = \frac{1}{2ab} \frac{-1}{2x(2a+b+2x)} = \frac{1}{2ab}](https://tex.z-dn.net/?f=+%5Cfrac%7B-1%7D%7B2x%282a%2Bb%2B2x%29%7D+%3D++%5Cfrac%7B1%7D%7B2ab%7D+)
On cross-multiplication, we get
![-2ab = 2x(2a+b+2x) -2ab = 2x(2a+b+2x)](https://tex.z-dn.net/?f=-2ab+%3D+2x%282a%2Bb%2B2x%29)
-2ab = 4ax + 2bx + 4x^2
4ax + 2bx + 4x^2 + 2ab = 0
2x^2 + 2ax + bx + ab = 0
2x(x + a) + b(x + a) = 0
(2x + b)(x + a) = 0
x = -a (or) x = -b/2
Hope this helps!
On cross-multiplication, we get
On cross-multiplication, we get
-2ab = 4ax + 2bx + 4x^2
4ax + 2bx + 4x^2 + 2ab = 0
2x^2 + 2ax + bx + ab = 0
2x(x + a) + b(x + a) = 0
(2x + b)(x + a) = 0
x = -a (or) x = -b/2
Hope this helps!
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