Math, asked by abdullaadhil5648, 10 months ago

Solve the following for x by factorisation
a²X²+(a²+b²)x+b²

Answers

Answered by pranav77764
0

..........................++7777++++....

Answered by dwivediakshansh23
0

Answer:

Step-by-step explanation:   a²b²x² – (a² - b²) x + 1 = 0

Solution:

a²b²x² – (a² - b²) x + 1 = 0

a²b²x² – a² x - b² x + 1 = 0

a²x (b² x – 1) -1(b² x – 1) = 0

(b² x – 1) (a² x – 1) = 0

(b² x – 1) = 0 (a² x – 1) = 0

b² x = 1 a² x = 1

x =1/b² x = 1/a²

Verification:

a²b²x² – (a² - b²) x + 1 = 0

if x = 1/a²

a²b²(1/a²)² – (a² - b²) (1/a²) + 1 = 0

b²/a² - a²/a² + b²/a² + 1 = 0

- 1 + 1 =0

hope it will be helpful to you

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