Math, asked by sunasangeeta636, 1 month ago

Solve the following
हल किो-
i) (2√5+3√3) + (3√5+ 4√3)
ii) 6√7 × 2√7
iii) 6√15÷3√5

Answers

Answered by TYKE
10

Question :

Solve the following :

i) (2√5+3√3) + (3√5+ 4√3)

ii) 6√7 × 2√7

iii) 6√15÷3√5

Solution :

 \sf \small i) (2√5+3√3) + (3√5+ 4√3)

 \sf \small \rightarrow2√5+3√5+ 3√3+ 4√3

 \sf \small \rightarrow  5√5+7√3

  \boxed{\sf \small Hence  \: the \:  answer \:  is    \green{\underline{\: 5√5 + 7√3}}}

 \sf \small ii) 6√7 × 2√7

 \sf \small \rightarrow6 \times 2 \times  \sqrt{7}  \times  \sqrt{7}

 \sf \small \rightarrow8 \times  {( \sqrt{7} )}^{2}

 \sf \small \rightarrow8 \times  7

 \sf \small \rightarrow56

  \boxed{\sf \small Hence \:  the  \: answer \:  i s   \:  \:  { \orange{ \underline{  \pink{56}}}}}

 \sf \small iii) 6√15÷3√5

 \sf \small \rightarrow \frac{6 \sqrt{15} }{3 \sqrt{5} }

 \sf \small \rightarrow2 \sqrt{5}

  \boxed{\sf \small Hence \:  the  \: answer \:  i s   \:  \:  { \orange{ \underline{  \blue{2 \sqrt{5} }}}}}

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