Question

solve the following half redox reaction in acidic Cr2 O7^2+2O2→Cr^3++5O4^2-​

Answer 1

Explanation:

The oxidation half reaction is SO

2

(g)+2H

2

O(l)→SO

4

2−

+4H

+

(aq)+2e

−

.

The reduction half reaction is Cr

2

O

7

2−

(aq)+14H

+

(aq)+6e

−

→2Cr

3+

(aq)+7H

2

O(l).

The oxidation half reaction is multiplied by 3 and added to the reduction half reaction to obtain the balanced redox reaction.

Cr

2

O

7

2−

+3SO

2

(g)+2H

+

(aq)→2Cr

3+

(aq)+3SO

4

2−

(aq)+H

2

O(l)