Math, asked by shin3333, 1 month ago

Solve the following:
i) (3-y)/4 =9
ii) 7(2x-5) = 63
iii) 3x+4 = 22
iv) 2/3 x = 12
v) 3(x-1)+6 = 12

Answers

Answered by sureshbm12
1

Answer:

01. -y=12

02.x=7

03.x=18/3

04.x=8

05.x=3

Step-by-step explanation:

01. (3-y)/4=9

3-y=9×4

3-y=36

-y=36/3

-y=12

02. 7(2x-5)=63

2x-5=63/7

2x-5=9

2x=9+5

2x=14

x=14/2

x=7

03.3x+4=22

3x=22-4

3x=18

x=18/3

04.2/3x=12

3x=12×2

3x=24

x=24\3

x=8

05.3(x-1) +6=12

3x-3+6=12

3x-3=12-6

3x-3=6

3x=6+3

3x=9

x=9/3

x=3

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