Math, asked by sripathiramesh9866, 5 months ago

Solve the following
(i) log,32 = x (i) log,625 =y
(iv) log, 16 = 2 .: x² = 16 = x= +4,

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Answers

Answered by mamtaadh960
0

Step-by-step explanation:

log 32 =x

x = 2 power 5

x=5

log 625=y

y=25

log, 16 = 2

log =8

x² = 16 = x= +4,

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