Question

Solve the following:
(i) x + 3 = 11;
(ii) y − 9 = 21;
(iii) 10 = z + 3;
(iv) $\frac{3}{11} + x = \frac{9}{11}$
(v) 10x = 30;
(vi) $\frac{s}{7} =4$
(vii) $\frac{3x}{6} = 10$
(viii)$1.6= \frac{x}{1.5}$
(ix) 8x − 8 = 48;
(x) $\frac{x}{3} + 1= \frac{7}{15}$
(xi) $\frac{x}{5} =12$
(xii) $\frac{3x}{5} = 15$
(xiii) 3(x + 6) = 24;
(xiv) $\frac{x}{4} -8 =1$
(xv) 3(x + 2) − 2(x − 1) = 7.

Answer 1

I) x=8
2)y=30
3)z=7
4)x=12/11
5)x=300
6)s=28
7)x=20
8)x=2.4
9)x=7
10)x=7/5
11)x=60
12)x=2
13)x=2
14)x=3
15)x=5/12