Question

Solve the following identities

1)x^2-7 > 0
2)x^2-3x > 0
3)x^2-3x+2 > 0

Plz. Help me guys nd in this problem I will mark u brainlist if they r ryt.

Answer 1

Hey friend, Harish here.

Here is your answer:

$1) \ \ x^2 - 7 \ \ge \ 0 \\ \\ \to x^2 \ \ge \ 7 \\ \\ \to Then,\ x \ \ge \ \sqrt{7} , x \ \le \ - \sqrt{7} \\ \\ \boxed{\bold{Therefore \ x \ \ge \ \sqrt{7} , x \ \le \ - \sqrt{7} } }} \\ \\ 2)\ \ x^2 -3x \ \ge \ 0 \\ \\ \to x^2 \ \ge \ 3x \\ \\ \to x \ \le \ 3 \\ \\ \boxed{\bold{Therefore,\ x \ \ge \ 3 , x \ \le \ 0}}\\ \\ 3) \ \ x^2 -3x + 2 \ \ge \ 0 \\ \\ \to (x-2) (x-1) \ \ge \ 0 \\ \\ \boxed{\bold{Therefore,\ x\ \ge \ 2 , x\ \le \ 1}}$
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Hope my answer is helpful to you.