Question

solve the following in a+ib form
(-2-1/3i)^3​

Answer 1

Answer

using the identity (a+b)3=a3+b3+3ab(a+b)

(−2)3+(−13i)2+3(−2)(−13i)(−2−13i)

=−8−127i3+2i(−2−13i)

=−8+127i−4i−23i2

=−8+127i−4⋅2727i−23(−1)

=−8+23+129i−10827i

=−223−107i27

a=−223&b=−10727

answer

Step-by-step explanation:

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Answer 2

Answer:

= 22/3-107i/27( after simplifying both real and imaginary parts...