Question

solve the following in elimination method 2x+3y=8 ,4x+6y=7​

Answer 1

Step-by-step explanation:

didn't difined there is a error

Answer 2

$\bold\pink{2x + 3y = 8}$

$\bold\purple{4x + 6y = 7}$

${\fbox{\red{Multiply \: by \: 4}}}$

$\bold\blue{4x + 6y = 16}$

${\fbox{LHS \: of \: i \: and \: ii \: are \: same \: but \: RHS\: is \: different}}$

${\fbox{\orange{Hence \: the \: solution \: does \: not \: exist}}}$.