Question

Solve the following in Simultaneous equation
x - 3y = 1;
3x - 2y = - 4
​

Answer 1

Given :

• x - 3y = 1 &
• 3x - 2y = - 4

To Find :

• The value of x and y.

According to the question,

➝ x - 3y = 1 ...(i)

➝ 3x - 2y = - 4 ...(ii)

From equation (ii),

➝ x - 3y = 1

➝ x = 1 + 3y

Putting the value of x in equation (ii),

➝ 3x - 2y = - 4

➝ 3(1 + 3y) - 2y = - 4

➝ 3 + 9y - 2y = - 4

➝ 3 + 7y = - 4

➝ 7y = - 4 - 3

➝ 7y = - 7

➝ y = -7 ÷ 7

➝ y = -1

Substituting the value of y in equation (i),

➝ x - 3y = 1

➝ x - 3(-1) = 1

➝ x + 3 = 1

➝ x = 1 - 3

➝ x = -2

• Hence, the value of x is -2 and the value of y is -1.

Answer 2

• x−3y=1
• x−3y=1y=
• x−3y=1y= 3
• x−3y=1y= 3x−1
• x−3y=1y= 3x−1
• x−3y=1y= 3x−1
• x−3y=1y= 3x−1 ∣x=1,4,7∣
• x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣
• x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0
• x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0y=
• x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0y= 2
• x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0y= 23x+4
• x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0y= 23x+4
• x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0y= 23x+4
• x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0y= 23x+4 ∣x=0,2,4∣
• x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0y= 23x+4 ∣x=0,2,4∣∣y=2,5,8∣
• x−3y=1y= 3x−1 ∣x=1,4,7∣∣y=0,1,2∣3x−2y+4=0y= 23x+4 ∣x=0,2,4∣∣y=2,5,8∣The solution of the given equations is the point of intersection of the two lines i.e (-2, -1)