Question

solve the following inequalities graphically in two
dimentional plane​

Answer 1

Answer:

Consider the equation x = -3. Draw a graph of x = -3 by dotted line, which is parallel to y-axis, to the left of y-axis at distance Put x = 0 in the given inequation x > -3, we get 0 > -3 which is true. ∴ Solution region consists of (0, 0). ∴ The shaded region is the solution region (ii) y < -2 ………….(1) Consider the equation y = -2. Draw a graph of y = -2 by dotted line, which is parallel to x-axis, below x-axis and at distance 2. Put y = 0 in (1), 0 < -2 which is not true. ∴ Solution region is not containing (0, 0). ∴ Shaded region is the solution region. (iii) x + y < 5 ………….(1) Draw the graph of x + y = 5 by dotted line. Points (5, 0) and (0, 5) lie on it. Join these points. Put x = 0 and y = 0 in (1), we get 0 + 0 < 5 which is true. ∴ The solution region contains the origin. ∴ The shaded region is the solution region (iv) 2x- 3y > 6 ………….(1) Draw the graph of 2x – 3y = 6 by dotted line It passes through (3, 0) and (0, -2). Join these points. Put x = 0 and y = 0 in (1), we get 0 – 0 > 6 which is not true. ∴ Solution region does not contain the origin Read more on Sarthaks.com - https://www.sarthaks.com/586990/solve-the-following-inequalities-graphically-in-two-dimensional-plane-i-x-3-ii-y-2-iii-x-y-5