Question

solve the following inequalities taking (1, 2,3,4,5,6,7,8) as replacement set
$3( x + 3) \leqslant 26 - x$
please solve it fast! ​

Answer 1

Answer:

No oppa I didn't updated my brainly app

Since Saturday it's not working-_-

Answer 2

Answer:

Given: −

Given: − 3

Given: − 3x

Given: − 3x

Given: − 3x ≤

Given: − 3x ≤ 2

Given: − 3x ≤ 2x

Given: − 3x ≤ 2x

Given: − 3x ≤ 2x −1

Given: − 3x ≤ 2x −1 3

Given: − 3x ≤ 2x −1 31

Given: − 3x ≤ 2x −1 31

Given: − 3x ≤ 2x −1 31 <

Given: − 3x ≤ 2x −1 31 < 6

Given: − 3x ≤ 2x −1 31 < 61

Given: − 3x ≤ 2x −1 31 < 61

Given: − 3x ≤ 2x −1 31 < 61

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.−

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6−

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 3

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6<

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 6

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61 ×6

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61 ×6−2x≤3x−8<1

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61 ×6−2x≤3x−8<1⇒−2x≤3x−8 and 3x−8<1

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61 ×6−2x≤3x−8<1⇒−2x≤3x−8 and 3x−8<1⇒8≤3x+2x ⇒3x<1+8

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61 ×6−2x≤3x−8<1⇒−2x≤3x−8 and 3x−8<1⇒8≤3x+2x ⇒3x<1+8⇒8≤5x ⇒3x<9

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61 ×6−2x≤3x−8<1⇒−2x≤3x−8 and 3x−8<1⇒8≤3x+2x ⇒3x<1+8⇒8≤5x ⇒3x<9⇒

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61 ×6−2x≤3x−8<1⇒−2x≤3x−8 and 3x−8<1⇒8≤3x+2x ⇒3x<1+8⇒8≤5x ⇒3x<9⇒ 5

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61 ×6−2x≤3x−8<1⇒−2x≤3x−8 and 3x−8<1⇒8≤3x+2x ⇒3x<1+8⇒8≤5x ⇒3x<9⇒ 58

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61 ×6−2x≤3x−8<1⇒−2x≤3x−8 and 3x−8<1⇒8≤3x+2x ⇒3x<1+8⇒8≤5x ⇒3x<9⇒ 58

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61 ×6−2x≤3x−8<1⇒−2x≤3x−8 and 3x−8<1⇒8≤3x+2x ⇒3x<1+8⇒8≤5x ⇒3x<9⇒ 58 ≤x ⇒x<3

Given: − 3x ≤ 2x −1 31 < 61 Taking L.C.M. of 3,2 and 6 is 6.− 3x ×6≤ 2x ×6− 34 ×6< 61 ×6−2x≤3x−8<1⇒−2x≤3x−8 and 3x−8<1⇒8≤3x+2x ⇒3x<1+8⇒8≤5x ⇒3x<9⇒ 58 ≤x ⇒x<3∴ The solution set is {x:1.6≤x≤3,xϵR}

Step-by-step explanation:

Heres ur answer MR.SHIVAM (+_+)