Question

Solve the following inequality
x^2-4x+3/x^2+x+1<0​

Answer 1

Answer:

x > 2/5

Step-by-step explanation:

$\sf \Rightarrow \dfrac{ {x}^{2} - 4x + 3}{ {x}^{2} + x + 1 } < 0$

⇒ x² - 4x + 3 < x² + x + 1

⇒ x² - x² - 4x - x < 1 - 3

⇒ - 5x < - 2

⇒ - x < - 2/5

Multiplying by - 1 on both sides

⇒ x > 2/5