Question

Solve the following inequality
x^2+6x-27>0 and -x^2+3x+4>0​

Answer 1

Answer:

${x}^{2} + 6x - 27 > 0 \\ = > {x}^{2} + 9x - 3x - 27 > 0 \\ = > x(x + 9) - 3(x + 9) > 0 \\ = > (x - 3)(x + 9) > 0 \\ by \: representing \: on \: number \: line \: \\ x€( - \infty ,- 9) U (3, \infty )$