Math, asked by sunitabisht, 1 year ago

solve the following inequatiom and write down the solution set: 11x-4<15x+4<13x+14, x=whole numbers​

Answers

Answered by shubham9362
26

Step-by-step explanation:

11 x -4 <15x+4 <13x +14; x€ w

11x -15x <4+4

-4x<8

-4x<2

x>-2

15x +4<13 x+14

15x-13x<14-4

2x<10

x<5

Set={0,1,2,3,4}

Answered by syed2020ashaels
1

Answer:

Our solution set becomes x={0,1,2,3,4}

Step-by-step explanation:

It is given to us that 11 x -4 &lt; 15x+4 &lt; 13x +14 where x€ w

By using the first inequation we get

11x-4 &lt; 15x+4\\11x -15x &lt; 4+4\\-4x &lt; 8\\-x &lt; 2\\x &gt; -2

Now by using second inequation we get

15x +4 &lt; 13 x+14\\15x-13x &lt; 14-4\\2x &lt; 10\\x &lt; 5\\

From above two conditions our solution set becomes x={0,1,2,3,4}
#SPJ3

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