Question

Solve the following inequation :​

Answer 1

Step-by-step explanation:

|2x-4| >2|x+1|

let us square both sides

|2x-4|² > 2|x+1|²

4x²- 16x+16> 2(x²+2x+1)

4x²-2x²-16x-4x+16-2 >0

2x²-20x+14> 0

(div.2)» x²- 10x+7 > 0

x = -b±(√b²-4ac) / 2a

= 10 ± √ 100-28 / 2(1)

= [10± √ 72] /2

x = 5± 3√ 2

X ≥ 5± 3√2

or

|2x-4| >2|x+1|

let us square both sides

|2x-4|² > 2|x+1|²

4x²+16> 2(x²+1)

4x²-2x²+16-2 >0

2x²+14> 0

x² >-14/2

|x| > i√7

choose the crt ans I don't know which is right