Question

solve the following inequations x+10>4x-5

question 11 class ka hi
question no 2nd hi
modern math hi​

Answer 1

$\large\underline{\sf{Solution-}}$

Given inequality is

$\rm :\longmapsto\:x + 10 > 4x - 5$

Subtracting 4x from both sides, we get

$\rm :\longmapsto\:x + 10 - 4x> 4x - 5 - 4x$

$\rm :\longmapsto\:10 - 3x> - 5$

On Subtracting 10 from both sides, we get

$\rm :\longmapsto\:10 - 3x - 10> - 5 - 10$

$\rm :\longmapsto\: - 3x > -15$

$\bf\implies \:x < 5$

$\bf\implies \:x \: \in \: ( - \infty , \: 5)$

Additional Information :-

$\red{ \boxed{ \sf{ \:x > y \: \: \bf\implies \: \: - \: x \: < \: - \: y}}}$

$\red{ \boxed{ \sf{ \:x < y \: \: \bf\implies \: \: - \: x \: > \: - \: y}}}$

$\red{ \boxed{ \sf{ \:x < - y \: \: \bf\implies \: \: - \: x \: > \: y}}}$

$\red{ \boxed{ \sf{ \:x > - y \: \: \bf\implies \: \: - \: x \: < \: y}}}$

$\red{ \boxed{ \sf{ \:x \geqslant - y \: \: \bf\implies \: \: - \: x \: \leqslant \: y}}}$

$\red{ \boxed{ \sf{ \:x \leqslant - y \: \: \bf\implies \: \: - \: x \: \geqslant \: y}}}$

$\red{ \boxed{ \sf{ \: - \: x \leqslant - y \: \: \bf\implies \: \: x \: \geqslant \: y}}}$

Answer 2

Answer:

$x + 10 > 4x - 5 \\ \\ 10 + 5 > 4x - x \\ \\ 15 > 3x \\ \\ 5 > x$

Hope it will help you ✌️