Question

solve the following
int a= 4 , b= 5
I) a+=a++-(b--*a++)/--b+b
2) a=a++*++b/(--b+a++)
3) b*=b+++++b*--a%3
4) a=/=a*b+++--a
5) b+=b++*a++/++b*--b


very very urgent please help​

Answer 1

$\huge\red{Ans}\green{wer}$

This question is about increment and decrement operators. So , we will solve this in steps.

step 1: a = 6 (given)

step 2: b = (++a) + (a++) + (a++) ————(1)

just break this statement into three parts,,,and take first of them..

1) ++a = 7 (pre-increment) so (6+1=7) will be assigned to a.

2) a++ = 7 (post increment) it will remain same here,then value of a will be 8 in next step.

3) a++ = 8 (post increment) so now value of a will be 9 for further.

step 3: Now put the values of these three sub-steps in eq. (1) to get the value of b.

b = 7+7+8 = 22.

step 4 .in sub-step (3) we can say value of a = 9.

so,a = 9, b = 22.