Question

Solve the following :

integration dx/1-sin x​

Answer 1

$\int \: \frac{1}{1 - sinx}dx \\ = \int \: ( \frac{1}{1 - sinx} \times \frac{1 + sinx}{1 + sinx}) dx \\ = \int \: \frac{1 + sinx}{ {cos}^{2}x } dx \\ = \int \: ( {sec}^{2} x + secxtanx )\: dx \\ = tanx + secx + \large c$

Answer 2

Step-by-step explanation:

$integration dx \1 + sinx$