Question

SOLVE THE FOLLOWING. JAIMIN TAKES RS. 10000 AT 12%PER YEAR AS RATE OF INTEREST, FOR 2 YEARS. HOW MUCH INTEREST HE HAS TO PAY AT THE END OF TWI YEARS?​

Answer 1

Answer:

Solution: Amount to be paid=principal amount+Simple interest Simple interest=`(P xx RxxT)/100` where P is the principal amount ,T is time and R is the

Answer 2

$\Large {\underline {\underline {\text {\maltese \ {\red {Question :-}}}}}}$

Jaimin takes Rs. 10,000 at 12% per Annum as Rate of Interest for 2 Years.

How much Interest he has to Pay at the End of 2 Years?

$\Large {\underline {\underline {\text {\maltese \ {\red {Solution :-}}}}}}$

Given,

Principal Amount, P = Rs. 10,000

Rate of Interest, R = 12% p.a.

Time Period, t = 2 Years

We know that, $\bold {Simple\: Interest} = \bold {\frac {Principal \times Rate\: of\: Interest \times Time}{100}}$

On Substituting these Values, we get -

$\begin {aligned} \bold {Simple\: Interest} & = Rs. \ \dfrac {10000 \times 12 \times 2}{100}\\\\\\& = Rs. \ \dfrac{2400 \cancel {00}}{1 \cancel {00}} = \bold {Rs. \ 2400} \end {aligned}$

Hence, Jaimin has to Pay an Interest of Rs. 2,400 at the End of 2 Years . . .