Math, asked by aanchalgarg343, 7 months ago

Solve the following Lagrange's linear equation:
(2x^2 + y^2 +z^2 – 2 yz – zx – xy)p + (x^2 + 2 y^2 + z^2 - yz – 2zx - xy)q=
(x^2 + y^2 + 2z^2 - yz – zx – 2xy)​

Answers

Answered by princegauravadarshi
0

Step-by-step explanation:

2x^2 + y^2 +z^2 – 2 yz – zx – xy)p + (x^2 + 2 y^2 + z^2 - yz – 2zx - xy)q=

(x^2 + y^2 + 2z^2 - yz – zx – 2xy)2x^2 + y^2 +z^2 – 2 yz – zx – xy)p + (x^2 + 2 y^2 + z^2 - yz – 2zx - xy)q=

(x^2 + y^2 + 2z^2 - yz – zx – 2xy)2x^2 + y^2 +z^2 – 2 yz – zx – xy)p + (x^2 + 2 y^2 + z^2 - yz – 2zx - xy)q=

(x^2 + y^2 + 2z^2 - yz – zx – 2xy)2x^2 + y^2 +z^2 – 2 yz – zx – xy)p + (x^2 + 2 y^2 + z^2 - yz – 2zx - xy)q=

(x^2 + y^2 + 2z^2 - yz – zx – 2xy)

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