Question

solve the following ley elimination method ×+y=6 and 3×-y=10​

Answer 1

Answer:

x+y=6 ----(1)

3x-y=10 -----(2)

now, (1) +(2)

x+y+3x-y=6+10

now y is cancelled

hence, 4x=16

and x = 4 ---(3)

putting x in (1)

4+y=6

y=6-4

=2

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Answer 2

Answer:

x-value = 4

y-value = 2

Coordinate points: (4, 2)

Step-by-step explanation:

We can write to two equations given, one after the other to solve for x-value first:

 x + y = 6

3x - y = 10

since y and -y are reciprocals of each other, they will be eliminated and we are left with:

x = 6

3x = 10

Adding the like terms would give us;

4x = 16

x = 16/4

x = 4

Now that we have the x-value as 4, we can substitute in 4 for x in any of the given equation to solve for y;

x + y = 6

(4) + y = 6

y = 6 - 4

y = 2

Therefore the answer to this system of equation is when;

x-value = 4

y-value = 2

Therefore the coordinate points would be; (4, 2)

Hope this helps!