Question

Solve the following linear equation÷
1)
$\frac{7x + 1}{4x - 5} = \frac{1}{3}$
2)The dum of digits of a two digit number is 11.The number formed by reversing the digits exceds the given number by 27,find the number . ​

Answer 1

(7x + 1) × 3 = (4x - 5) × 1

21x + 3 = 4x - 5

3 + 5 = 4x - 21x

17x = -8

x = -8/17

Sum of two digit number = 11

Let unit’s digit be ‘x’

and tens digit be ‘y’,

then x+y=11…(i)

and number = x+10y

By reversing the digits,

Unit digit be ‘y’

and tens digit be ‘x’

and number =y+10x+27

Now by equating both numbers,

y+10x+9=x+10y

10x+y–10y–x=−9

9x–9y=−9

x–y=−1…(ii)

Adding (i) and (ii), we get

2x=10

x=10/2

=5

∴y=1+5=6

By substituting the vales of x and y, we get

Number = x+10y

=5+10×6

=5+60

=65

∴ The number is 65

Hope it helps you and please mark me brainliest.

Answer 2

Answer:

The dum of digits of a two digit number is 11.The number formed by reversing the digits exceds the given number by 27,find the number

Step-by-step explanation:

having tension...

due to this headache is increasing, even tho when I stood up from my place, I wasn't able to see anything, for few instance black was appearing Infront of my eyes, I hope you get it what I mean;)

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