Question

solve the following linear equation 15(y-4)-2(y-9)+5(y+6)=0​

Answer 1

Answer:

15y-60-2y+18+5y+30=0

-12y-12= 0

-12y = 12

y = -1

$mark \: as \: brainlist$

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Answer 2

$\huge\purple{ \underline{ \boxed{\mathbb{\red{QUESTION : }}}}}$

$\small \textsf{Solve: 15 ( y - 4) - 2 ( y - 9) + 5 ( y + 6 ) = 0}$

$\huge\purple{ \underline{ \boxed{\mathbb{\red{ANSWER : }}}}}$

$\large\displaystyle { \color{red} \sf y = \frac{2}{3} }$

$\green{ \large \underline{ \mathbb{\underline{GIVEN : }}}}$

$\textsf{15 ( y - 4) - 2 ( y - 9) + 5 ( y + 6 ) = 0}$

$\green{ \large \underline{ \mathbb{\underline{TO \: FIND : }}}}$

$\red{ \overline\textsf{\underline{Value of y .}}}$

$\green{ \large \underline{ \mathbb{\underline{SOLUTION: }}}}$

$\begin{array}{l} \\ \hline \\ \small \sf{15 ( y - 4) - 2 ( y - 9) + 5 ( y + 6 ) = 0} \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\ \\\small \sf15y - 60 - 2y + 18 + 5y + 30 = 0 \\ \\ \small \sf15y - 2y + 5y - 60 + 18 + 30 = 0 \\ \\ \small \sf13y + 5y - 60 + 48 = 0 \\ \\ \small \sf18y - 12 = 0 \\ \\ \small \sf18y = 12 \\ \\ \small \displaystyle\sf y = \frac{12}{18} \\ \\ \small \displaystyle\sf y = \frac{2}{3} \\ \\ \hline\\ \end{array}$