solve the following linear equation:
2x - 3y = 3
2x/3 + 4y =6
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What is the solution to the simultaneous equations 2x+3y=3 and 3x+4y=6?
One method is substitution.
I solve
2x+3y=3
for x because it has the smaller coefficient. Solving for y is acceptable, too.
2x=3−3y
means that
x=3−3y2.
Replace x by this expression in the equation
3x+4y=6
and get
3(3−3y2)+4y=6.
Multiply through by 2 to clear the equation of the fraction:
2(3)(3−3y2)+2(4y)=2(6)
which means that
3(3−3y)+8y=12.
Remove parentheses:
9−9y+8y=12.
Collect terms and get
9−y=12.
Get y by itself:
9−12=y,
that is,
y=−3.
Now go back to the formula obtained for x and replace y by −3:
x=3−3(−3)2=3+92=122,
that is,
x=6.
These answers should be checked in the given equations to make sure that there are no mistakes
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