Math, asked by aadwiktandon0123, 12 days ago

solve the following linear equation

3/5y-2=7/10

Answers

Answered by AachleshMule
1

Step-by-step explanation:

3

5

2

=

7

1

0

\frac{3}{5} \cdot y-2=\frac{7}{10}

53⋅y−2=107

Solve

1

Combine multiplied terms into a single fraction

3

5

2

=

7

1

0

3

5

2

=

7

1

0

2

Add

2

2

2

to both sides of the equation

3

5

2

=

7

1

0

3

5

2

+

2

=

7

1

0

+

2

3

Simplify

Add the numbers

Add the numbers

3

5

=

2

7

1

0

4

Multiply all terms by the same value to eliminate fraction denominators

3

5

=

2

7

1

0

5

3

5

=

5

2

7

1

0

5

Simplify

Cancel multiplied terms that are in the denominator

Multiply the numbers

3

=

2

7

2

6

Divide both sides of the equation by the same term

3

=

2

7

2

3

3

=

2

7

2

3

7

Simplify

Cancel terms that are in both the numerator and denominator

Divide the numbers

=

9

2

Show less

Solution

=

9

2

Answered by kshivamsatyam
1

Y = 9/2

I hope it will help you.

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