solve the following linear equation
30/x-y +44/x+y = 10
40/x-y + 55 / x - y = 13
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let 1/x-y=a and 1/x+y=b
then the equations are
30a+44b=10
40a+55b=13
multiply equation 1 with 4 and equation 2with 3
120a+176b=40
120a+165b=39
subtract the equations
then 11b=1
b=1/11 then a=1/5 it means that
1/x+y=1/11 and 1/x-y=1/5
x+y=11 and x-y=5
by solving the equations we will get x=3 and y=8
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