Solve the following linear equation
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Answered by
2
hi....
substitute value of y from 1st eq. in 2nd eq.
y=p-q-px / q
by substituting,
q^2x-p(p-q-px / q) =p+q
by solving,
x(p^2 + q^2) = p^2 + q^2
therefore, x=1
by substituting in eq.1
we get y = -1
hope it helps....
substitute value of y from 1st eq. in 2nd eq.
y=p-q-px / q
by substituting,
q^2x-p(p-q-px / q) =p+q
by solving,
x(p^2 + q^2) = p^2 + q^2
therefore, x=1
by substituting in eq.1
we get y = -1
hope it helps....
Answered by
2
px+qy=p-q
qx-py=p+q
Multiple eq is p and multiple eq2 q
p^2x+pqy=p^2-q
q^2x-pqy=p+q^2
x(p^2+q^2)=p-q+p^2+q^2
X=p-q+p^2+q^2÷p^2+q^2
Now put the value of x in eq 1
Px+qy=p-q
p(p-q+p^2+q^2)÷(p^2+q^2)+qy=p-q
Y=p-q-p(p-q+p^2+q^2)/(p^2+q^2)÷q
qx-py=p+q
Multiple eq is p and multiple eq2 q
p^2x+pqy=p^2-q
q^2x-pqy=p+q^2
x(p^2+q^2)=p-q+p^2+q^2
X=p-q+p^2+q^2÷p^2+q^2
Now put the value of x in eq 1
Px+qy=p-q
p(p-q+p^2+q^2)÷(p^2+q^2)+qy=p-q
Y=p-q-p(p-q+p^2+q^2)/(p^2+q^2)÷q
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