Question

solve the following linear equation​

Answer 1

$5( \frac{7x + 5}{3} ) - \frac{23}{3} = 13 - \frac{4x - 2}{3} \\ \\ \frac{35x + 25 - 23}{3} = \frac{39 - 4x - 2}{3} \\ \\ 35x + 2 = 37 - 4x \\ \\ 39x = 35 \\ \\ x = \frac{35}{39}$

Answer 2

Answer:

5(7x+5)/3 – 23/3 = 13 – (4x-2)/3

By rearranging

(35x + 25)/3 + (4x – 2)/3 = 13 + 23/3 (35x + 25 + 4x – 2)/3 = (39+23)/3 (39x + 23)/3 = 62/3

By cross-multiplying

(39x + 23)3 = 62(3) 39x + 23 = 62 39x = 62 – 23 39x = 39

(39x + 23)3 = 62(3) 39x + 23 = 62 39x = 62 – 23 39x = 39 x=1

Let us verify the given equation now

5(7x+5)/3 – 23/3 = 13 – (4x-2)/3

By substituting the value of ‘x’ we get,

(35x + 25)/3 – 23/3 = 13 – (4x-2)/3 (35+25)/3 – 23/3 = 13 – (4-2)/3 60/3 – 23/3 = 13 – 2/3 (60-23)/3 = (39-2)/3 37/3 = 37/3

35x + 25)/3 – 23/3 = 13 – (4x-2)/3 (35+25)/3 – 23/3 = 13 – (4-2)/3 60/3 – 23/3 = 13 – 2/3 (60-23)/3 = (39-2)/3 37/3 = 37/3 1=1